Bash Command Not Found Variable

2021 06 16 linuxeden fixed mac command not found error in terminal zsh bash. php weixin 39868592 csdn linux unzip linuxgod.

Bash Command Not Found Variable

2 Answers Sorted by 15 In shell spaces are not allowed on either side of the in a variable assignment Try this instead variable This is a variable If you leave a space before the the shell parses the token before it as a command or function name which is why you see the command not found message Share Improve this answer Follow Hexo bug tan s blog. Spring php How to fix bash wget command not found error guide .

2021 06 16 Linuxeden

1 You need do export ID ID COUNT ID ID COUNT VALUE Nasir Riley Dec 8 2018 at 4 43 Thanks for your response But can you explain why I need to do that I thought the export command is used for making a variable in a the current shell available in its sub shell This for loop doesn t run in a sub shell 2 Answers Sorted by: 2 That's not the way to do indirection unfortunately. To do what you want you could use printf like so printf -v "$bar" "1" which will store the value printed (here 1 in the variable name given as an argument to -v which when $bar expands here will be foo Also, you could use declare like declare "$bar"=1

Command Not Found In Bash Fixed Devconnected

Bash Command Not Found VariableBash Command Not Found Error with $variable Ask Question Asked 7 years ago Modified 4 years, 4 months ago Viewed 2k times 0 108 ps --ppid $process | while read -r line ; do 109 #echo $line | awk ' {print $1;} 110 child=$ ($line | awk ' {print $1;}') 111 echo $child 113 done Running this code gives me the following error: Command not found error in Bash variable assignment 6 answers Closed 7 years ago I have a shell script that will let me access global variables inside the script but when I try to create my own it responds with command not found bin bash J 4 FACE NAME eig J face USER DB NAME base J user When I run the above script I get

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